Question

A field is in the form of a right triangle with hypotenuse 10 m and one side 8 m. Find the area of the field​

Answer 1

Answer:

A=24 m²

a=8m

c=10m

A=ab by 2

c=√a²+b²

A=1by 2 a √c²-a²=1by2.8 √10²-8²=24m²ans

Answer 2

Answer :-

24 sq.m

Explanation :-

Given :

• Hypotenuse = 10m.
• One Side = 8m.

Need to Find :

• Area of field.

Solution :

We will use Pythagoras theorem.

Formula Used :- H² = P² + B²

➠ 10² = 8² + B²

➠ 100 = 64 + B²

➠ B² = 100 - 64.

➠ B² = 36.

➠ B = 6m.

Now, Calculating Area of Triangle.

$\underline{\boxed{\bf\pink{Area \: of \: Triangle = \dfrac{1}{2} \times b \times h}}}$

$\implies{\sf{Area \: of \: Triangle = \dfrac{1}{2} \times 6 \times 8}}$

$\implies{\sf{Area \: of \: Triangle = 3 \times 8}}$

$\implies{\textsf{\textbf{Area of Triangle = \red{24sq. m}}}}$

Therefore, Area of Triangle = 24 sq.m.

NOTE :-

Refer to the attached picture for diagram.