Question

A field is in the form of a trapazium. Its area is 1575 meter square and the distance between it's parallel sides is 26m. If one of the parallel sides is 84m, Find the other​

Answer 1

Answer:

$area \: of \: trapezium = 1575 {m}^{2} \\ height = 26m \\ one \: of \: the \: parallel \: side \: (a) = 84m \\area \: of \: trapezium = \frac{1}{2} \times sum \: of \: parallel \: side \: \times distance \: between \: parallel \: side \\1575 = \frac{1}{2} \times (a + b) \times h \\ 1575 = \frac{1}{2} \times (84 + b) \times 26 \\ 1575 = (84 + b) \times 13 \\ \frac{1575}{13} = (84 + b) \\ \frac{1575}{13} - 84 = b \\ \frac{1575 - 84 \times 13}{13} = b \\ \frac{1575 - 1092}{13} = b \\ \frac{483}{13} = b \\ b = \frac{483}{13} \\ b = 37 \frac{2}{13} m$

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