Question

A field is in the form of a triangle. If the length of the base of the field is 200 m and its area is 17,500 m-,
find the altitude of the field.​

Answer 1

Answer:

175m

Step-by-step explanation:

base= 200m

area=17500m

Now,

=>area of ∆= 1/2×base×altitude

=>17500= 1/2×200× altitude

=>17500/100= altitude

=> 175= altitude

Hence the altitude of ∆ field is 175m.

hope it helps..

Answer 2

Answer:

175

Step-by-step explanation:

Base=200

Area=17500 m

area of triangle=1/2×base×altitude

17500. =1/2×200×altitude (2 and 2 cut)

17500. =100×altitude

17500/100. =altitude

both zero is cut only remaining 175

so,answer is

175= altitude