Question

a field is in The form of The Number 8.The top portion is a circle of radius 14m and The bottom portion is a circle of radius 21m.one metre of The circumference of Both The circles touch each other.while going around The field ,how much total distance does one have to walk,leaving out this 1 metre distance.

Answer 1

Answer:

Step-by-step explanation:

Circumference =2πr

=2×22/7×14

=88m

=88-1=87m

Answer 2

$\underline\bold{\huge{solution!!}}$

Circumference of upper circle with radius 14 m

$= 2 \times \frac{22}{7} \times 14$
$= 88 \: m$

Circumference of lower circle with radius 21 m

$= 2 \times \frac{22}{7} \times 21$
$= 132 \: m$

Total distance one have to walk,leaving out this 1 metre distance

= (132 + 88 ) - 1+1

= 220 - 2

= 218 m