Question

A field is in the shape of a quadrilateral ABCD.
AB = 127 metre, BC = 206 metre, CD = 332 metre,
AD = 94 metre, BD = 183 metre
Calculate its area.​

Answer 1

Answer:

stion 10:

Find the perimeter and area of the quadrilateral ABCD in which AB = 17 cm, AD = 9 cm, CD = 12 cm, ∠ACB = 90° and AC = 15 cm.

ANSWER:

We assume ABCD be the quadrilateral having sides AB, BC, CD, DA and ∠ACB = 90∘.

We take a diagonal AC, where AC divides ABCD into two triangles ΔACB and ΔADC

Since ∆ACB is right angled at C, we have

AC = 15 cm; AB = 17 cm

AB2 = AC2 + BC2

Area of right angled triangle ABC, say A1 is given by

, where,

Base = BC = 8 cm; Height = AC = 15 cm

Area of triangle ADC, say A2 having sides a, b, c and s as semi-perimeter is given by

, where

a = AD = 9 cm; b = DC = 12 cm; c = AC = 15 cm

Area of quadrilateral ABCD, say A

A = Area of ∆ACB + Area of ∆ADC

Perimeter of quadrilateral ABCD, say P