Question

a field is in the shape of a quadrilateral ABCD in which a b is equal to 6 cm is equal to 10 cm is equal to 12 CM BC is equal to 13 cm angle DBC is equal to 90 degree find the area and the perimeter

Answer 1

Given;- ABCD is quadrilateral

and it's divided into two triangles ABD and BCD.

In Triangle ABD ;- 1/2 * 18 * 24 = 216 cm^2

BC^2 = AB^2 + AD^2    =>  BC = 30 cm


semi perimeter = 60 cm

 area = sqroot(60 * 30 * 20 * 10 ) = 600 cm^2

Total area Of a
quadrilateral = 816 cm^2


Thanks me Later ❤️