Question

A field is in the shape of a trapezium having parallel sides 90 m and 30 m. These sides meet the third side at right angles. The length of the fourth side is 100 m. If it costs Rs 4 to plough 1m2 of the field, find the total cost of ploughing the field.​

Answer 1

Step-by-step explanation:

✿ᑫᑌᗴՏTIOᑎ:-

A field is in the shape of a trapezium having parallel sides 90 m and 30 m. These sides meet the third side at right angles. The length of the fourth side is 100 m. If it costs Rs 4 to plough 1m2 of the field, find the total cost of ploughing the field.

✿ᗩᑎՏᗯᗴᖇ:-

◉ՏOᒪᑌTIOᑎ:-

$Let \: the \: field \: in \: the \: shape \: of \: a \\ trapezium \: be \: PQRS \: where \: PS \: ll \: QR \\ \: and \:∠ P \: and \: ∠Q \: are \: 90°$

$Here \: PS \: =90m, \: RQ \: =30m \:and \: \: SR \: =100m$

$Draw \: a \: ⊥ \: RT \: from \: point \: R \: on \: to \: SP.$

$Now \: RT \: =PQ \: and \: RT \: ∥ \: PQ.$

$Hence \: ST \: = \: 90 \: − \: 30 \: = \: 60 \: m$

$Applying \: Pythagoras′ \: Theoremin \: △ \: STR,$

$TR= \: \sqrt{(100 {}^{2} - 60 {}^{2} )}$

$= \: \sqrt{(10000 - 3600)}$

$= \sqrt{6400}$

$= 80cm.$

$So, \: the \: PQ= \\ height \: of \: the \: trapezium \: =80 \: m$

$The \: area \: of \: the \: trapezium \: PQRS$

$= \frac{1}{2} \: ×PQ \: × \: (RQ+SP)$

$= \frac{1}{2} ×80×(90+30)$

$=40×120 \\ =4800$

$Cost \: of \: ploughing \: 1 \: field \: =Rs. \: 4$

$∴Cost \: of \: plouging \: 4800 \: field \\ =4×4800 \\ =Rs. \: 19200$

Answer 2

Step-by-step explanation:

Photosynthesis is the process by which plants use sunlight, water, and carbon dioxide to create oxygen and energy in the form of sugar.