Question

a field is in the shape of a trapezium, its parallel sides are 40 m and 85 m and the
distance between the parallel sides is 12 m. Find the cost of ploughing the field at the rate of rupee 12/m²
please step by step explained ​

Answer 1

Answer:

Area of trapezium= a+b÷2×h

Here a= 40m, b= 85m and h=12m

So a+b÷2×h =40+85/2. × 12=550m²

Cost of ploughing 1m²= Rs. 12

Cost of ploughing 550m²= 550×12 =Rs. 6600

Answer 2

Given:

• Parallel sides= 40m and 85m
• Distance between Parallel sides = height = 12m
• Cost of plugging = 12 Rupees per${m}^{2}$

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Need to find:

• The cost of ploughing the field =?

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Solution:

$\setlength{\unitlength}{1.5cm}\begin{picture}\thicklines\qbezier(0,0)(0,0)(1,2.2)\qbezier(0,0)(0,0)(4,0)\qbezier(3,2.2)(4,0)(4,0)\qbezier(1.5,2.2)(0,2.2)(3,2.2)\put(0.8,2.4){ \bf A }\put(3,2.4){ \bf D }\put(-0.3,-0.3){ \bf B }\put(4,-0.3){ \bf C }\put(4.4,0){\vector(0,0){2.2}}\put( 4.4, 0){\vector(0,-1){0.1}}\put(4.6,1){ \bf 12\ m }\put(0, -0.5){\vector(1,0){4}}\put(0, -0.5){\vector( - 1, 0){0.1}}\put(1.7, - 0.9){ \bf 85\ m  }\put(0.8, 2.8){\vector(1,0){2.5}}\put(0.8, 2.8){\vector( - 1, 0){0.1}}\put(1.7, 3){ \bf 40\ m  }\end{picture}$

Let,

• AD = 40m
• BC= 85m
• And Height = h= 12m

Area of the trapizium:

$= \dfrac{1}{2} \times (sum \: of \: masure \: of \: parallel \: sides) \times height$

$= \dfrac{1}{2} (40 + 85) \times 12 {m}^{2}$

$= \dfrac{1}{2} \times 125 \times 12 \: {m}^{2}$

$= \dfrac{1}{2} \times 1500 \: {m}^{2}$

$= 750 \: {m}^{2}$

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The cost will be :

= 750 × 12 rupees

= 9000 Rupees

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$\therefore$ The cost of ploughing will be 9000 Rupees.