Question

A field is in the shape of a trapezium. Its parallel sides are 42 m and 30 m long. The (3) distance between the parallel side is 28 m. Find the area of the field

Answer 1

Given:

• Shape of field is Trapezium.
• Parallel sides of field are 42m and 30m
• Distance between parallel sides is 28m

To Find:

• Area of field?

We known that,

Area of Trapezium = $\small{\sf{\dfrac{1}{2}}\times (sum~of~parallel~sides)\times height}$

Therefore,

Area of field = $\small{\sf{\dfrac{1}{2}}\times (sum~of~parallel~sides)\times height}$

$\small{\implies\sf{\dfrac{1}{2}}\times (42+30)\times 28}$

$\small{\implies\sf{\dfrac{1}{\cancel{2}}}\times 72\times {\cancel{28}}}$

$\small{\implies{\sf{72\times 14}}}$

Area of field = 1008

Hence,

$\large{\boxed{\bf{\pink{Area~of~trapezium~shaped~field~is~1008m^2}}}}$

Related Formula:

• Area of rectangle = Length × Breadth
• Perimeter of rectangle = 2(Length + Breadth)
• Area of square = side²
• Perimeter of square = 4×side
• Area of triangle = $\dfrac{1}{2}$ ×Base×Height
• Perimeter of triangle = Sum of sides
• Area of parallelogram = Base × Height
• Perimeter of parallelogram = Sum of sides
• Area of circle = π × radius²
• Perimeter of circle 2π × radius

Answer 2

Answer:

Given:

Shape of field is Trapezium.

Parallel sides of field are 42m and 30m

Distance between parallel sides is 28m

To Find:

Area of field?

We known that,

Area of Trapezium = \small{\sf{\dfrac{1}{2}}\times (sum~of~parallel~sides)\times height}

2

1

×(sum of parallel sides)×height

Therefore,

Area of field = \small{\sf{\dfrac{1}{2}}\times (sum~of~parallel~sides)\times height}

2

1

×(sum of parallel sides)×height

\small{\implies\sf{\dfrac{1}{2}}\times (42+30)\times 28}⟹

2

1

×(42+30)×28

\small{\implies\sf{\dfrac{1}{\cancel{2}}}\times 72\times {\cancel{28}}}⟹

2

1

×72×

28

\small{\implies{\sf{72\times 14}}}⟹72×14

Area of field = 1008

Hence,

\large{\boxed{\bf{\pink{Area~of~trapezium~shaped~field~is~1008m^2}}}}

Area of trapezium shaped field is 1008m

2