Question

A field is in the shape of a trapezium whose parallel sides are Im and 2m. The mon parallel sides are
Im each. Find the area of the field.​

Answer 1

Answer:

Step-by-step explanation:

Let ABCD is a trapezium such that AB = 35m, BC = 13 m, CD = 10 m and DA = 14 m

Draw a line DE parallel to the side BC =13 m therefore DE = 13 m

AE+ED+DA = 15+13+14 = 42

2s= 42 or s = 21

Area of triangle DAE using Hero's formula = sqrt{ 21(21-15)(21-14)(21-13)} = 84 m^2............(i)

DF is a perpendicular from D on AE= h

Area of triangle = (1/2)(15)(h)...............................

from (i) and (ii)

(15/2)*h = 84

h = (84*2)/15 = 11.2 m...................................(iii...

Area of parallelogram = 10*11.2 = 112 m^2...........................(iv)

Therefore area of trapezium = Area of triangle+ Area of parallelogram

= 84 +112 = 196 m^2..............................Ans

Hope it was helpful

Answer 2

Above one is correct