A field is in the shape of a trapezium whose parallel sides are 25m and 10m.The non-parallel sides are 14m and 13m. Find the area of the field.
Answers
Answer:
196m^2
Step-by-step explanation:
Let the given field be the shape of a trapezium ABCD in which AB=25m,CD=10m,BC=13m and AD=14m
From D,draw De//BC meeting AB at E
Now draw DFperpendicular toAB
DE=BC=13m
AE=AB-AC
=25-10=15m
For triangle ADE
a=14m,b=15m,c=13m
S=a+b+c/2
=14+15+13/2
=42/2
=21m
Area of triangle ADE=√s(s-a)(s-b)(s-c)
=√21(21-14)(21/15)(21-13)
=√21*7*6*8
=√7*3*7*2*3*4*2
=7*3*2*2
=84m^2
DF perpendicular to AE
For triangle ADE
Area of triangle ADE=1/2bh
=1/2*15*h
IE,1/2*15*h=84
h=84*2/15
h=56/5m
Height of the parallelogram EBCD=56/5m
Area of the parallelogram ABCD=b*h
=10*56/5
=112m^2
Area of the field=84m^2+112m^2
=196m^2
Answer:
hey enjoy from this answer
