A field is in the shape of trapezium . One of its parallel sides is twice the other parallel side and distance between them is100 m . If the area of the field is 10,500 sq m find the length of parallel sides
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Answered by
31
Hello Mate!
Here, we know that area of trapezium includes
= 1/2 × h ( a + b )
Now, as given if one parallel side is a then another is 2a
10500 m^2 = 1/2 × 100 m ( 2a + a )
10500 m^2 × 2 × 1/100 m = 3a
210 m = 3a
210 m / 3 = a
70 m = a,
Another parallel sides are = 2a = 2 × 70 m
= 140 m
Hope it helps☺!✌
Here, we know that area of trapezium includes
= 1/2 × h ( a + b )
Now, as given if one parallel side is a then another is 2a
10500 m^2 = 1/2 × 100 m ( 2a + a )
10500 m^2 × 2 × 1/100 m = 3a
210 m = 3a
210 m / 3 = a
70 m = a,
Another parallel sides are = 2a = 2 × 70 m
= 140 m
Hope it helps☺!✌
pariee:
Tysm
Answered by
11
solution.
Area of trapezium= 1/2 (Sum of ||side) * height
=> 10500= 1/2 (x+2x) *100
=> 10500= 3x *50
=> 210=3x
=> x= 70
so,smaller side= 70m
larger side= 2*70= 140m
___________
✌✌
Area of trapezium= 1/2 (Sum of ||side) * height
=> 10500= 1/2 (x+2x) *100
=> 10500= 3x *50
=> 210=3x
=> x= 70
so,smaller side= 70m
larger side= 2*70= 140m
___________
✌✌
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