Question

a field is in the shAPE OF trapezium whose parallel sidescare 25m abd 10m the non-parallel sides are 14m and 13m find the area of the field

Answer 1

Let the length of height = y m so, 25 = √(14² - y²) + 10 + √(13² - y²) 15 = √(14² - y²) + √(13² - y²) 15 - √(13² - y²) = √(14² - y²) on squaring both sides, we get 225 + 169 - y² - 30√(13² - y²) = 196 - y² 198 - 30√(13² - y²) = 0 33 = 5√(169 - y²) on squaring both sides, we get 3136 = 25y² so, y = 56/5 so, area = (1/2)(25 + 10)× (56/5) = 196 sq.m

Answer 2

Answer:

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