Math, asked by niraj979850, 8 months ago

a field is in the shape of trapezium whose parallel sides are 2.5 and 10 the non parallel sides are 14 and 13 find the area of field​

Answers

Answered by akankshsksinha7
1

Answer:

Area of trapezium = 1/2*2.5+10*height

Answered by dimprajapati
4

SOLUTION :

⇒ Area of trapezium

  = 1/2*Sum of parallel*height

  =1/2*(AB+DC)*BF

 

⇒Draw BE parallel to AD

Since,opposite sides are parallel,

ABED is a parallelogram

In  parallelogram opposite sides are equal

⇒BE=AE=13cm

⇒ED=AB=10m

Also, EC=DC-ED

⇒25-10

⇒15m

Area of the triangle = s(s-a)(s-b)(s-c)

  a=14m , b=15m, c=13m

therefore, s=21m

Area of triangle BEC = 86m^2

area of field is 196m^2

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