Question

A field of 5 * 10^4/pi ampere- turns/meter acts st right angles to a coil 50 turns of area 10^-2 m^2 the coil is removed from the field in 0.1 seconds then the induced emf in the voil is

Answer 1

Answer:

Explanation:

B = μ0H

=μ0×5×10^4π

e = NBA / time

=50×2×10^−2×10^−2 / 0.1

=0.11

Correct answer is 0.1 V

Answer 2

Dear Student,

◆ Answer -

EMF = 0.1 V

● Explanation -

# Given -

H = 5×10^4/π A.turns/m

n = 50 turns

A = 10^-2 m^2

t = 0.1 s

# Solution -

EMF induced in the coil is given as -

EMF = nBA/t

EMF = μ0nHA/t

EMF = 4π×10^-7 × 50 × 5×10^4/π × 10^-2 / 0.1

EMF = 0.1 V

Hence, EMF induced in the coil is 0.1 V.

Thanks dear. Hope this helps you...