Question

a fielder takes a catch 3s after the player has hit the ball assuming the fielder takes the catch at the same height at which the ball was hit. (1) how high did the ball rise (2) the final velocity of the ball​

Answer 1

fielder takes a catch 3s after the player has hit the ball assuming the fielder takes the catch at the same height at which the ball was hit. is 3sseconds. As the distance travelled b is the same so, let us take the distance travelled during both upward and downward motion to be ‘d’ meters each. So as per the 1st equation of motion,

v = u+at

In the case of the upward journey,

v = 0 m/s, a = -10 m/s^2 and since the time of both the upward and downward journies is the same so t for upward journey = t for downward journey = 3/2

as per the above mentioned equation

0 = u - 10 x 3/2

0 = u - 15

u = 15m/s

Now as per the 2nd equation of motion,

s = ut + 1/2 at^2

s = 15m/sx 3 + 1/2 x -10 x 9

s = 45- 45

s = 0