a fighter plan can cover 490 km in 7/3 hours .how much distance will it cover in 31/7 hours?
Answers
Answered by
3
distance=490km
time=7/3 h
speed of the plane=distance/time
= 490×3/7
=70×3=210km/h
so now distance covered by it in 31/7 hours=speed of plane ×time
=210×31/7=30×31=930kms
time=7/3 h
speed of the plane=distance/time
= 490×3/7
=70×3=210km/h
so now distance covered by it in 31/7 hours=speed of plane ×time
=210×31/7=30×31=930kms
Similar questions
Computer Science,
7 months ago
Science,
7 months ago
Science,
7 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Physics,
1 year ago
Hindi,
1 year ago