Question

A fighter plane flying horizontal at an altitude of 2km with speed of 540 kmph passes directly over head an anti-aircraft gun if the gun can fire a bullet at the muzzle speed of 500 ms at what angle with vertical the gun should fire the bullet so that the bullet hits the plane

Answer 1

Answer:

See below.

Explanation:

In order to hit the plane, the horizontal velocity of the plane and the bullets ( muzzle velocity ) have to be equal. See the diagram.

$\frac{500}{cos \theta} = 540$

Therefore,

$cos \theta = \frac{50}{54} = 0.926$

The value of theta,

$\theta = cos^{-1}( 0.926 ) = 22.18^{\circ}$