Physics, asked by riza2462, 11 months ago

A fighter plane flying horizontal at an altitude of 2km with speed of 540 kmph passes directly over head an anti-aircraft gun if the gun can fire a bullet at the muzzle speed of 500 ms at what angle with vertical the gun should fire the bullet so that the bullet hits the plane

Answers

Answered by shubham0204
2

Answer:

See below.

Explanation:

In order to hit the plane, the horizontal velocity of the plane and the bullets ( muzzle velocity ) have to be equal. See the diagram.

\frac{500}{cos \theta} = 540

Therefore,

cos \theta = \frac{50}{54} = 0.926

The value of theta,

\theta = cos^{-1}( 0.926 ) = 22.18^{\circ}

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