Question

A fighter plane flying horizontally at an altitude of 1.5 km with speed 720 km/h passes directly overhead an anti-aircraft gun. At what angle from the vertical should the sun be fired for the shell with muzzle speed 600 ms to hit the plane ? At what min altitude should the pilot fly the plane to avoid being hit? (Take g = 10 ms.

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Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Velocity of plane, vo=720 x 5/180 ms

1 = 200m * s ^ - 1

Velocity of shell = 600 ms

200 600 sin 0 = 1 3

or = sin -1 G 1 3 = 19.47°

This angle is with the verticle.

Let h be the required minimum height

sin 0 =

(3) This angle is with the verticle.

or 0

=

sin

= 19.47°

Let h be the required minimum height

Using equation v ^ 2 - u ^ 2 = 2as we get

(0) ^ 2 - (600cos theta) ^ 2 = - 2 * 10h

or h = (600 * 600 * (1 - sin^2 theta))/20

=

30 * 600 * (1 - 1/9) = 8/9 * 30 * 60 * l