Question

A fighter plane is flying horizontally at an altitude of 1.5km with speed 540km/h. The angle of line of sight with respect to horizontal, when the target is seen the pilot should drop the bomb in order to hit that target is......(g=10m/s^2) a)60 b)45 c)30 d)15 please answer with steps...

Answer 1

Explanation:

Time & flight =t=a2s,a=g

Than H=vt=720km/h×9.8m/sec22×1500m

=3.5km

tanθ=3.51.5km=.428

θ=tan−1.428=23.17∘

≃23∘4′

take this as an example... ok and solve it yourself