Question

a fighter plane is flying horizontally at an altitude of 1.5 kilometres with a speed 720 kilometre per hour at what angle of site with respect to the horizontal with the target seen should the pilot drop the bomb in order to attack the target?​

Answer 1

Answer:

Explanation:

 \[\tan \,\theta =\frac{h}{R}\]                 But \[R=\,u\times \,\sqrt{\frac{2h}{g}}\]  

 \[\therefore \]\[\,\tan \,\theta \,=\,\frac{h}{u\times \,\sqrt{\frac{2h}

  or \[\tan \theta =\,\frac{1}{u}\,\sqrt{\frac{gh}{2}}=\,\frac{1}{200}\,\times \,\sqrt{\frac{10\times \,1500}{2}}\]                 \[=0.4330\]                 \[\therefore \]\[\,\theta =\,{{\tan }^{-1}}\,(0.4330)\,={{23.4}^{o}}.\]

Answer 2

Answer:

23°12'

Explanation:

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