Question

A fighter planeflying horizontally at an altitude 1.5 km with a speed of 720 km flues over an Anticraft gun. At what angle should the shell be fired from the gun to hit the fighter plane with a muzzle speed of 400 m/s

Answer 1

Explanation:

Given A fighter plane flying horizontally at an altitude 1.5 km with a speed of 720 km flues over an Anticraft gun. At what angle should the shell be fired from the gun to hit the fighter plane with a muzzle speed of 400 m/s

• Given the horizontal distance travelled by the shell = distance travelled by plane.
• Height of fighter plane = 1.5 km = 1500 m
• Speed of fighter plane = 720 km / hr = 720 x 1000 / 60 x 60 = 200 m/s
• Let theta be angle with the vertical so that shell hits the plane.
• Muzzle velocity of the gun u = 400 m/s
• Time taken by shell to hit the plane = t
• So horizontal distance travelled by shell will be Uzt
• Distance travelled by plane = vt
• The shell hits the plane so the two distances must be equal.
• Now u sin theta t = v t
• Therefore sin theta = v/u
•           So sin theta = 200 / 400
•                              = 1/2  
• So theta = sin ^-1 ½
• So theta = 30 degree

Reference link will be

https://brainly.in/question/1382660