A filament bulb rated 60 W operates 8
hours/day. What is the cost of the energy to
operate it for 30 days at Rs.5 per KWH.
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Answer:
Power of refrigerator =600W=0.6kW
Total operation hours 8×30=240h
Work done or total electrical energy (W)=0.6×240=144kWh
Total cost of energy to operate =Rs.(144×4.00)=Rs.576
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