Question

a filament of an electric bulb draws a current of 0.5 A for 6 hours calculate the amount of charge that is flown in the circuit​

Answer 1

Answer:

10800coulumb

Explanation:

I=q/t

q=It

I=0.5

t=6×60×60=21600second

q=0.5×21600=10800

q=10800coulumb

I hope it will help you

Answer 2

Given:-

Amount of current drawn = 0.5 A

Time for which current drawn = 6 hours = 6 × 3600 = 21600 seconds

To find :-

The amount of charge flow in the circuit.

Solution:-

Let the amount of charge flow in circuit will be Q.

Form current formula,

I = Q / T

also,

Q = I * T

$\implies$ Q = $\frac{5}{10} \times 216000$

$\implies$ $5 \times 21600$

$\implies$ $1.08 \times {10}^{5} q$

hence,the amount of charge flow in circuit will be 1.08 × 10^5 Columb.