Question

A file of cadets consisting of ten rows and five columns measures 420 m in length along the direction of their
marching. How much time (in hours and minutes) would it take to march for a stretch of 3 km, if the stride of
each cadet is 80 cm, and he takes 57 strides per minute?
O1 hr 15 min
0 1 hr 20 min
O 1 hr 24 min
O 1 hr 10 min​

Answer 1

Explanation:

1 hr 15 min

Answer 2

Given :- A file of cadets consisting of ten rows and five columns measures 420 m in length along the direction of their marching. How much time (in hours and minutes) would it take to march for a stretch of 3 km, if the stride of

each cadet is 80 cm, and he takes 57 strides per minute?

A) 1 hr 15 min

B) 1 hr 20 min

C) 1 hr 24 min

D) 1 hr 10 min .

Solution :-

given that,

→ stride of each cadet = 80 cm. = (80/100) = 0.8 m.

and,

→ Each cadet takes strides in 1 minute = 57

So, we can say that,

→ in 60 seconds he cover = (57 * 0.8) m .

→ in 1 second he cover = (57 * 0.8) / 60 = 0.76m .

Therefore, we can conclude that,

→ Speed to cover the distance = 0.76m/s.

Now,

→ Total distance to be covered = 420m(Distance to be covered by last cadet) + 3000 m (3km) = 3420 m.

Hence,

→ Total time taken to march for a stretch of 3km = (Total distance) / speed = (3420/0.76) = 4500 seconds = (4500/3600) = (5/4) hours = 1 hour + (1/4 * 60) = 1 hour 15 minutes . (Option A) (Ans.)

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