A file of cadets consisting of ten rows and five columns measures 420 m in length along the direction of their A marching. How much time (in hours and minutes) would it take to march for a stretch of 3 km. if the stride of each cadet is 80 cm, and he takes 57 strides per minute?
O 1 hr 20 min
O 1 hr 10 min
O 1 hr 24 min
O 1 hr 15 min
Answers
Answered by
18
Answer:
1 hr 15 min
Explanation:
So total distance need to be covered by last cadet
=> D = 420
Speed = [(80/100) * 5.7 * (1/60)] per sec
= 76/100 m/sec
Now
T=D/S
T= (3420 x 100) /76 = 4500 sec
= 75 min = 1 hr 15 min
Answered by
1
Answer:
1hr 15 min
Explanation:
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