A file of cadets consisting of ten rows and five columns measures 420 m in length along the direction of their marching. How much time (in hours and minutes) would it take to march for a stretch of 3 km, if the stride of each cadet is 80 cm and he takes 57 strides per minute?
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If we consider the file of cadets as one single unit and want this unit to cover a stretch of 3 km, we effectively want the first row of cadets to cover a distance of 3 km + 420 m = 3420 m
Speed of each cadet = 0.8 m/stride * 57 strides/min = 0.8*57 m/min
So, time taken = 3420 m / (0.8*57) m/min = 75 mins
Step-by-step explanation:
LENGTH OF THE COLUMN = 420 m
MARCHING STRETCH = 3000 m
SPEED OF MARCHING= 57*80 = 4560 cm = 45.60 m/min
IF THE FIRST ROW HAS TO REACH 3 km, TIME TAKEN = 3000/45.6 = 65.79 m
IF THE LAST ROW HAS TO CLEAR, TIME TAKEN = (3000+420)/45.6 = 75 m
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