Question

A film of oil, refractive index 1.20, lies on water of refractive index 1.33. A light ray is incident at 30 degree in the oil-water boundary. calculate the angle of refraction

Answer 1

The angle of refraction is 27 degree.

Explanation:

=> It is given that,

Refractive index of oil, μ$_{oil}$ = 1.20

Refractive index of water, μ$_{water}$ = 1.33

Incident angle, i = 30°

Refraction angle, r = ?

=> According to the snell's law:

sin i / sin r = μ$_{water}$ / μ$_{oil}$

∴ sin 30 / sin r = 1.33/1.20

sin r = sin 30 * 1.20 / 1.33

sin r = (1/2) * 120 / 133

sin r = 0.45

r = sin⁻¹ (0.45)

r = 27°

Thus,  the angle of refraction is 27 degree.

Learn more:

Q:1 The refractive index of two media are 1.7 and 1.333 .calculate velocity of light in these two media

Click here: https://brainly.in/question/3308298

Q:2 State Snell’s law of refraction of light. Express it mathematically. Write the relationship between absolute refractive index of a medium and speed of light in vacuum.

Click here: https://brainly.in/question/2927124

Answer 2

Answer:

According to the snell's law:

According to the snell's law:sin i / sin r = μ_{water}water / μ_{oil}oil

According to the snell's law:sin i / sin r = μ_{water}water / μ_{oil}oil∴ sin 30 / sin r = sin r = 1.33/1.20sin r = sin 30 * :sin i / sin r = μ_{water}water / μ_{oil}oil∴ sin 30 / sin r = 1.33/1.20sin r = sin 30 * 1.20 / 1.33sin r = (1/2) * 120 / 133

sin r = 1.33/1.20sin r = sin 30 * 1.20 / 1.33sin r = (1/2) * 120 / 133sin r = 0.45

According to the snell's law:sin i / sin r = μ_{water}water / μ_{oil}oil∴ sin 30 / sin r = 1.33/1.20sin r = sin 30 * 1.20 / 1.33sin r = (1/2) * 120 / 133sin r = 0.45r = sin⁻¹ (0.45)

=27