Math, asked by brmanjunath666, 1 day ago

A film show lasted for 3 1/3 hours out of this time 3/4 had spent on ad advertisement what was the actual duration of the film.​

Answers

Answered by khubaib2084
0

Answer:

here you go

Step-by-step explanation:

I hope you understand

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Answered by Ooguay
0

Answer:

2\frac{7}{12} hours

Step-by-step explanation:

3\frac{1}{3} = \frac{10}{3}

∴ total duration - advertisement time = duration of the film

= \frac{10}{3} - \frac{3}{4}

LCM of 3 and 4 = 12

\frac{10}{3} x \frac{4}{4} = \frac{40}{12}

\frac{3}{4}  x \frac{3}{3} = \frac{9}{12}

\frac{40}{12} - \frac{9}{12} = \frac{31}{12}

\frac{31}{12} = 2\frac{7}{12}

∴ The film lasted 2\frac{7}{12} hours

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