(A) Final the least number which when divided by 20,25,35
and leaves remainder
in each case
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Pls, mark Me Brainliest Answer:1394
Step-by-step explanation: First find out the LCM of 20,25,35 and 40
20=2×2×5
25=5×5
35=1×5×7
40=2×`2×2×5
LCM of 20,25,35 & 40 = 2×2×5×5×7×2=1400
when divided by 20,25,35,40 leaves a remainder 14,19,29,34
i.e 6 less than the divisor in each case
Hence the required number =1400−6=1394
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