Math, asked by pateshwaridubey, 1 month ago

(A) Final the least number which when divided by 20,25,35
and leaves remainder
in each case​

Answers

Answered by Anonymous
0

Pls, mark Me Brainliest Answer:1394

Step-by-step explanation: First find out the LCM of 20,25,35 and 40

20=2×2×5

25=5×5

35=1×5×7

40=2×`2×2×5

LCM of 20,25,35 & 40 = 2×2×5×5×7×2=1400

when divided by 20,25,35,40 leaves a remainder 14,19,29,34

i.e 6 less than the divisor in each case

Hence the required number =1400−6=1394

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