Question

a
Find :- 8x4 (x² + y ) where (x+y)
=5 and (x-4)=1​

Answer 1

Answer:

Find :- 8x4 (x² + y ) where (x+y)

=5 and (x-4)=1

Answer 2

Step-by-step explanation:

let equation 1,

3x+4y=5

and equation 2,

8x-4y=-16

in equation 1,

3x=5-4y

x=5-4y/3

in equation 2 putting the value of

Equation 1,

8(5-4y/3)-4y=-16

y=2

now x=5-4y/3

x=5-4*2/3

x=-1

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