Question

a) Find
a) Find out the oxidation number of Mn from the following compound
i) Mno
ii) KMnO4
iii) Mn20
b)Identify the oxidizing agent and reducing agent from given reaction
CuO+H2 ----> H2O +Cu​

Answer 1

Explanation:

(a) Let x be the oxidation number of Mn.

Since, the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0.

K 4 ; 2+x+4(−2)=0;x=+6

MnSO 4 ; x−2=0;x=+2

MnO 2 ; x+2(−2)=0;x=+4

Mn 3O 4 ; 3x+4(−2)=0;x= 8/3

The oxidation number of Mn in KMnO4 , K2MnO4 , MnSO4 , MnO2 and Mn3O 4is +7,+6,+2,+4 and + 8/3 respectively.

(b) oxidizing agent - cuo

reducing agent - h2