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Find Enet on centre due to
seni circular ring.
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PHYSICS
Find the electric field at the centre of a semicircular ring if it is uniformly positive charged.
December 26, 2019Surendar Dambal
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W split the semicircular arc into small segments ds. We have point charge on each segment as λds. The electric field due to this small segment of charge, from Coulomb's law,
dE=4πε0R21R2λds
Each little portion of the arc will give dE, in a different direction. We must therefore take components in order to find the total field at the centre.
Here, X-component of the electric field is zero. This is the result of the fact that dEx shown in the figure will be cancelled by the contribution from a symmetrically placed ds on the left half of the arc.
Hence we need only to compute dEy, which is vertically downward.
Explanation:
A wire, of length L(=20cm), is bent into a semi-circular arc. If the two equal halves, of the arc, were each to be uniformly charged with charges ±Q,[∣Q∣=10
3
ϵ
0
Coulomb where ϵ
0
is the permittivity (in SI units) of free space] the net electric field at the centre O of the semi-circular arc would be :
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