Question

a) Find out the total resistance and total current IT flowing through the circuit.



b) Write two differences between series and parallel connection.



c) Calculate the power used in R1.


pls help. ☹️​

Answer 1

Answer:

Sol. In the given circuit both 12 ohm resistors are connected in parallel, so their equivalent resistance R' = 4 ohm.

With this 4 ohm resistor, 6 ohm resistor are connected in series. So equivalent resistance of the circuit R'' = 4 + 6 = 10 ohm

=> Total resistance in the circuit = 10 ohm

We know, V = IR

=> I = V/R

=> I = 12 / 10 = 1.2 A

(b) Series connection: (1) Same current flows through all the components in the circuit.

(2) The equivalent resistance is always more than highest value of resistance in the series connection.

Parallel connection:(1) Different current flows through each component in the circuit.

(2) The equivalent resistance always has a less value than any of the single resistors connected parallely.

(c) We know Power , P = I²R

=> P = (1.2)²(6)

=> P = 8.64 W ( which is power through R1 )

Answer 2

Answer:

Rs = R1 + R2 + ...

Rp = R1R2/R1+R2

Explanation:

athey da entrance okke therakkurunnu, inatode subam ...୧⁠(⁠＾⁠ ⁠〰⁠ ⁠＾⁠)⁠୨

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ntha ppd..?