Question

a. Find
slope of
잉
cuve
y =
(x-2)^-2 at x=-2.​

Answer 1

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$y = {(x - 2)}^{ - 2} \\ differentiate \: with \: respect \: to \: x \\ \frac{dy}{dx} = - 2 {(x - 2)}^{ - 3} \\ \small\bold\red{slope \: of \: tangent \: at \: x = - 2 \: is} \\ - 2 {( - 2)}^{ - 3} \\ = ( - 2) \times ( - 8) \\ = 16$