Question

a) Find the area of a rectangle with length (x+3) units and breadth ( x -2) units.

Answer 1

Answer:

Area=x^2+x-6 sq units

Step-by-step explanation:

length=x+3

breadth=x-2

Area=length×breadth

Area=(x+3)(x-2)

Area=x^2+x-6 sq units

Answer 2

The area of a rectangle with length (x + 3) units and breadth ( x -2) units is x² + x - 6 sq.units

Given :

For a rectangle length is (x + 3) units and breadth is ( x -2) units

To find :

Find area of the rectangle

Solution :

Step 1 of 2 :

Write down length and breadth of the rectangle

For a rectangle length is (x + 3) units and breadth is ( x -2) units

Step 2 of 2 :

Find area of the rectangle

Area of the rectangle

= Length × Breadth

$\sf = (x + 3) (x - 2) \: \: \: sq.units$

$\sf = ( {x}^{2} + 3x - 2x - 6) \: \: \: sq.units$

$\sf = ( {x}^{2} + x - 6) \: \: \: sq.units$

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