Question

a Find the area of a right triangle with hypotenuse 13 cm and one of the perpendicular sides 12 cm. Use
Pythagoras theorem.​

Answer 1

Answer:

Consider the △ABC,

whereAC=13cm;BC=12cm by phythagorus theorm

AC

2

=AB

2

+BC

2

⇒AB

2

=AC

2

+BC

2

∴AB=

13

2

−12

2

=5cm

Area of △ABC=

2

1

×base×height

=

2

1

×AB×BC=

2

1

×12×5

=30cm

2

.

Answer 2

Step-by-step explanation:

Area of triangle = 1/2 × base × height

Here,

Hypotenuse (h) = 13 cm

Height Or perpendicular side (p) = 12 cm

Base (b) = ?

By pythogoras theorem

h²= p²+b²

b²=h²-p²

b= √h²-p²

b = √(13)²-(12)²

b= √169-144

b=√25

b= 5

Therefore,

Area of ∆= 1/2 × 5 × 12

= 30 cm²