Question

(a) Find the area of triangle with vertices A(2, 0), B(4, 5), C(6, 3).

(b) For what value(s) of a, the points (a, 0), (2, 0) and (4, 0) are collinear?​

Answer 1

Answer:

a............

triangle formula :- 1/2×[×1(y2-y3)+×2(y3-y1)+×3(y1-y2)]

1/2×[2(5-3)+4(3-0)+6(0-5) ]

1/2 ×[ 4+12-30]

1/2×(16-30)

-7 as 7 square units area .

b...............

as collinear means area is 0

according to triangle formula

0=1/2[a(0-0)+2(0-0)+4(0-0)

0= a(0-0)

0=a ...........as ..........a=0 ..

so the value of a is 0 .

Hopes its help u mark it as a brainlist answer .