Math, asked by archana31patel, 19 days ago

(a) Find the difference between the place value and face value of 9 in 3,09,812. a (b) Find the difference between the place values of 1 and 6 in the numbers 17,68,905. (c) Find the difference between the place values of two 7s in the numbers 72,08,763.​

Answers

Answered by rajahindmishra
0

Answer:

face value and place value

Step-by-step explanation:

309812

so face value will be 9

place value will be 9000

1768905

face value 1 6

place value 1000000 60000

7208763

face value 7 7

place value

7000000

700

see face value will always same

place value just see the number where it lies and after that how many digits are there just see and put them as 0

Answered by priysha09
2

Place value of the digit in a number is defined by its position in the number where as face value of the digit in the number is the actual value of the number.

In order to get place value of a digit, we multiply the digit by the value of its position. For eg. in number 12345, the place value of the number 4 is 40 as is is placed on tens position and the face value will be the digit itself, 4.

(a) Given

The number- 309812

To find: difference between the place value and the face value of 9.

Solution:

Place value of 9 - 9*1000 (since 9 is at 1000th place) = 9000

Face value- 9

Difference:- 9000-9= 8991

(b)Given

The number- 1768905

to find: difference between the place values of 1 and 6.

Solution:

Place value of 6 - 6*10000 (since 6 is at 10 thousandth place) = 60000

Place value of 1 - 1*1000000 (since 6 is at 10 lakhs place) = 1000000

Difference:- 1000000- 60000= 940000

(c)Given

The number- 7208763

To find: difference between the place values of 7s

Solution:

Place value 1st of 7 - 7*100(since 7 is at 10 hundredth place) = 700

Place value of 2nd 7 - 7*1000000 (since 7 is at 10 lakhs place) = 7000000

Difference:- 7000000- 700=  6999300

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