Question

a) Find the equivalent resistance of the circuit.

b) What is the potential drop V1 across resistor R1?

c) Find the current I2 through resistor R2. d) What power is dissipated by R2​

Answer 1

Answer:

The power dissipated by each resistor can be found using any of the equations relating power to current, voltage, and resistance, since all three are known. Let us use P=V2R P = V 2 R , since each resistor gets full voltage. Thus, P1=V2R1=(12.0 V)21.00 Ω=144 W P 1 = V 2 R 1 = ( 12.0 V ) 2 1.00 Ω = 144 W .

Answer 2

Answer:

The power dissipated by each resistor can be found using any of the equations relating power to current, voltage, and resistance, since all three are known. Let us use P=V2R P = V 2 R, since each resistor gets full voltage.

Thus,

P1=V2R1=(12.0 V)21.00 Q-144 W P 1 = V2 R1 = ( 12.0 V) 2 1.00

= 144 Watt