Question

(a) Find the escape velocity for the satellite from earth’s surface .

(b) The mass of the earth is nine times that of mars . The radius of the earth is twice that of mars .

The escape speed on earth is 12 km/sec . What is the escape speed on mars.(given that R=6400Km.)​

Answer 1

Answer:

Escape speed is v

e

=

R

2GM

=12 km/s on Earth's surface.

Now, the mass of Mars is one-ninth and radius is half that of Earth's.

So,

v

m

′

=

R/2

2G×M/9

=

3

2

×

R

2GM

=

3

2

×12=4

2

km/s