Question

a Find the length of a seconds' pendulum at a place where g = 10 m s-2 (Take n = 3.14) plz helh me with this question
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Answer 1

Explanation:

We've been given,

Time = 2seconds

Acceleration due to gravity = 10m/s²

Value of π = 3.14

Time period of pendulum is given by the formula,

$\displaystyle{T = 2\pi \sqrt{ \frac{l}{g}} }$

Substitute known values in the formula

$\implies \displaystyle{2 = 2×3.14² \sqrt{ \frac{l}{10} } }$

$\implies \displaystyle{}l = \frac{10}{3.14^{2}}$

$\implies \displaystyle{l = 1.01m.}$

Therefore, length of seconds pendulum is 1.01m.