Question

(a)Find the numbers such that their mean proportion is 10 and third proportion is 112.​

Answer 1

Let’s assume the required numbers be a and b.

Given, 14 is the mean proportional between a and b.

a: 14 = 14: b

ab = 196

a = 196/b …. (1)

Also, given, third proportional to a and b is 112.

a: b = b: 112

b2 = 112a …. (2)

Using (1), we have:

b2=112×(196/b)b2=112×(196/b)

b3=143×23b3=143×23

b = 28

From (1),

a = 196/ 28 = 7

Step-by-step explanation:

hope it is helpful

please mark me brainlest

Answer 2

Answer:

The number is 56.

Explanation:

Hope it helps you