Question

a) Find the perimeter of a rectangle whose adjacent sides are (x+4)² and (x-4)²​

Answer 1

Answer:

perimeter of the rectangle

=2(length+breadth)

=2{(x+4)^2+(x-4)^2}

=2{x^2+8x+16+x^2-8x+16}

=2(2x^2+32)

=4(x^2+16)

Answer 2

Answer:

${(x + 4)}^{2} = {x}^{2} + 8x + 16 \\ ( {x - 4)}^{2} = {x}^{2} - 8x + 16 \\ perimeter = 2( {x}^{2} + 16 + {x}^{2} + 16) \\ = 2(2x {}^{2} + 32) \\ = 4x {}^{2} + 64$