Question

a) Find the slope of the tangent at the point (3,1) on the curve x^2+y^2=4x-2.

b) Find the equation of the tangent to the curve y=x^3-3x+5 at (2,7).

pls.... find both fast.....​

Answer 1

Answer:

$\huge\red{Answer}$

The slope of a curve of

y=f(x) at x=a is f'(a) .

Let us find the slope of

f(x)=x3−x+2 at x=1

.

By taking the derivative,f')=3x2−1

By plugging in x=1 ,f'(1=3(1)2−1=2

Hence, the slope is 2

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