a)
Find the smallest number which when divided by 35, 56 and 81, leaves the remainder 5 in each
case.
Answers
Answered by
1
Answer:
7565
Step-by-step explanation:
First find the lcm of 35, 56 and 81.
LCM(35,56,81) = 7560
Now add 5 to 7560
=> 5 + 7560 = 7565
Hope it helps!!
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