Math, asked by manvir1419, 3 months ago

a)
Find the smallest number which when divided by 35, 56 and 81, leaves the remainder 5 in each
case.

Answers

Answered by royalivia2008

1

Answer:

7565

Step-by-step explanation:

First find the lcm of 35, 56 and 81.

LCM(35,56,81) = 7560

Now add 5 to 7560

=> 5 + 7560 = 7565

Hope it helps!!

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