(a) Find the smallest number which when divided by 45 and 60 leaves 7 as the
remainder in each case.
Answers
Answered by
0
Answer:
2707
Step-by-step explanation:
X=bq+r
=(45)(60)+7
=2700+7
=2707
Answered by
1
Step-by-step explanation:
The smallest number which when divided by 45 and 60 leaves the remainder in each case is 187.
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