Question

a)Find the sum of 10a2,-15a2,4a2,-3a2​

Answer 1

10a^2+(-15a^2)+4a^2+(-3a^2)

=10a^2-15a^2+4a^2-3a^2

=-5a^2+a^2

=-4a^2

Answer 2

Answer:

The required sum of the given numbers is $-4a^{2}$

Step-by-step explanation:

Concept: In math, addition is the process of adding two or more integers together. Addends are the numbers that are added, while the total refers to the outcome of the operation.

Given: The numbers are $10a^{2} ,(-15a^{2} ),4a^{2} ,(-3a^{2} )$

To find: The objective is to find out the sum of the given expression.

Solution:

The given numbers are $10a^{2} ,(-15a^{2} ),4a^{2} ,(-3a^{2} )$

Therefore,

$10a^{2} -15a^{2} +4a^{2} -3a^{2}\\=(10a^{2} +4a^{2} )-(15a^{2} +3a^{2} )\\=14a^{2} -18a^{2} \\=-4a^{2}$

Therefore, the required sum of the given numbers is $-4a^{2}$.

#SPJ2