(a) find the total area of the roads.
(b)find the total cost of levelling the roads at Rupees 5 per m^2
(c)find the area of the remaining portion of the plot.
Answers
Firstly ,we will try to understand the question with the help of a rough diagram. [Rough diagram in attachment]
We can now understand that The plot ,the roads and the leftover plot are in the shape of rectangles . Hence,we can suppose them as rectangles and continue.
(a.)Total area of roads =Total area of the plot-leftover area
=(170m×140m)-[{140m-3 (3m)}× (170m-4m)]
=23800sq.m-[{140m-9m}×166m]
=23800sq.m-[131m×166m]
=23800sq.m-21746sq.m
=2054sq.m
Answer:2054sq.m is the area of the roads.
(b.)Cost of levelling the roads=Area of the roads×Rate of levelling
=2054sq.m×(Rs.5/sq.m)
=2054×Rs.5
=Rs.10270
Answer:Rs.1p270 is the cost of levelling the roads.
(c.)Area of the remaining portion =Total area of the plot -area of the roads
=(170m×140m)-2054sq.m
=23800sq.m-2054sq.m
=21746sq.m
Answer:21746sq.m is the area of remaining portion.
