Math, asked by soumyasharma14, 9 months ago

a- Find the value of K for which the equation
has unique solution
x-2y=8
kx-10y=10

Answers

Answered by aryan073

0

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Answer:

Method(1)

Step-by-step explanation:

x-2y=8

x-2y-8=0

x=2y-8

put in the 2nd equations

k(2y-8)-10y=10

2ky-8k-10y-10=0

2y(k-10)-2(4k+5)=0

k=10

Method (2)

x-2y=8

kx-10y=10

multiply in equations (1) by5

5x-10y=40

kx-10y=10

5-k=30

5-k-30=0

-k-25=0

k=-25

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